# molar mass of h3po4

Can someone give me a step by step to the solution? work out the limiting reagent. molar mass of H3PO4 IS 97.99g/mol. Complete the following calculations for H3PO4.4 pts (1pt each) a. Mass H3PO4 consumed = 2.50 mol NaOH X (1 mol H3PO4 / 3 mol NaOH) X 97.99 g/mol = 81.7 g H3PO4 consumed. Mass H3PO4 remaining = 18.3 g H3PO4 remaining. Calculate the formula and molar mass. H3PO4 is a strong acid and corrosive. P4O10 + 6H2O ----> 4 H3PO4. What is the molar mass of H3PO4? d. How many H atoms are there in 2.5 mol H3PO4.2.5pt How many oxygen atoms are in one unit of H3PO4? moles of H3PO4 = 25.4 g x a million mol/ninety 8 g = 0.259 mol H3PO4 Kg of solvent = (100g - 25.4 g) = seventy 4.6 g = 0.0746 kg Molality = moles of solute/kg of solvent = 0.259 mol/0.0746 kg solvent Molality = 3.47m Molar mass of *2H3PO4 is 195.9904 g/mol Convert between *2H3PO4 weight and moles moles H2O = 12.0 g / 18.016 g/mol = 0.66607 mol. Molar Mass: 97.9952. Do a quick conversion: 1 grams H3PO4 = 0.010204583427424 mole using the molecular weight calculator and the molar mass of H3PO4. c. How many moles of PO43-ions are present in 2.5 moles of phosphoric acid, H3PO4? Example Reactions: • PH3 + 2 O2 = H3PO4 • 3 KOH + H3PO4 = K3PO4 + 3 H2O • H3PO4 + 5 HCl = PCl5 + 4 H2O • H3PO4 + 3 NH3 = (NH4)3PO4 • H3PO4 + NaOH = NaH2PO4 + H2O What am I doing wrong? 1. I don't know what to do with this, I tried: (.005 L)(x M) = (.055 L)(0.258 M) And I got 2.838 mol/L But the answer is wrong apparently. Solution The molar mass of H3PO4 is 97.99 g. The percent by mass of each of the elements in H3PO4 is calculated as follows: %H=(3(1.008 g) H/ 97.99 g H3PO4)*100%= 3.086% A 5.00 mL sample of an aqueous solution of H3PO4 requires 55.0 mL of 0.258 M NaOH to convert all of the H3PO4 to Na2HPO4. mole H3PO4 = 1430 g H3PO4 x 1 mole H3PO4/98 g H3PO4 = 15 moles. The molar mass of H3PO4 (phosphoric acid) is: 97.993 grams/mol. Calculations: Formula: H3PO4 Molar Mass: 97.9937 g/mol 1g=1.02047376515021E-02 mol Percent composition (by mass): Element Count Atom Mass %(by mass) Start with a liter of solution which is 1000 mLx 1.680 g/mL gives a mass of 1680 g. mass H3PO4 = 1680 g solution x 85 parts H3PO4/100 parts solution = 1430 g H3PO4. Now there is 15 moles of H3PO4 in the initial liter so it is 15M H3PO4! The other product of the reaction is water. Mass Na3PO4 formed = 0.833 mol X 163.9 g/mol = 137 g Na3PO4 b. The one that produces the least H3PO4 is the limiting reagent. - 13159451 ams) has entries 4.9, 14.7. The third column labeled Mass of Washers m subscript w (kilograms) has entries 0.0049, empty. moles P4O10 = mass / molar mass = 10.00 g / 283.88 g/mol = 0.035226 mol. To do this work out how much H3PO4 you would get if all of each reagent individually were to fully react. From its MSDS sheet it is 1.680g/mL. H3PO4 is a colorless viscous liquid at room temperature. 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